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int bits_set = bitveccount();

Step 1: For the new input frame It , nd the closest pj to the pose estimates at t 1, that is, pt 1 . Assume motion m to be zero, and assume illumination condition t = t 1 . Apply the pose transformation operator W to l l p W (p m) , that is, get the pose normalized version of the frame I pt 1 j t 1 It (Wpt 1 (u, pj pt 1 m)). This is shown in Figure 7.2, where the input frame It on the manifold is rst warped to I which is within a nearby region of pose pj . Step 2: Use Eq. (7.8) to alternately estimate ci , and ce of the pose normalized image l, It

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There are two ways to set an individual bit Either the set() operation or the subscript operator can be used For example, the following for loop turns on each even-numbered bit:

The user may simply want to use a communication service provided by the access network For instance, a user may want to use her cellular phone to place a call, accessing a cellular network, or use her 80211 card to connect her laptop to her company network On the other hand, the goal of the user may be to connect to a service provider on the Internet In this case, the user is using the access network to simply gain connectivity to the service provider s network The user may have to use different communications devices to gain connectivity through each type of access network Each of these access networks typically has specific requirements on identification and security This means the user needs to obtain a set of network-specific identity and credentials to be able to connect to that particular access network.

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for ( int index = 0; index < 32; ++index ) if ( index % 2 == 0 ) bitvec[ index ] = 1;

Similarly, there are two ways to test whether an individual bit is turned on The test() operation takes the bit position as an argument and returns either true or false For example:

(7.16)

if ( bitvectest( 0 )) // our bitvec[ 0 ] worked!;

Again, alternatively, the subscript operator can be used:

cout "bitvec: positions turned on:\n\t"; for ( int index = 0; index < 32; ++index ) if ( bitvec[ index ] ) cout index " "; cout endl;

Denoting the basis for the identity and expression as E and F, we can similarly compute them as Epj = ZBj 1 l ce p Fpj = ZCj 1 l 3 ci p

For instance, to connect to a third generation (3G) cellular network, besides the cellular phone, the user needs to be provisioned with a phone number, an IMSI (International Mobile Subscriber Identity) and a SIM card, while to connect to a WLAN using LEAP authentication, the user needs a WLAN interface card along with a user name and password that the WLAN administrator recognizes First of all, this means the user needs to obtain a set of identity and credentials for each of the access networks she is connecting to Second, the user must trust the device that she is using to connect to that network not to reveal her identity and credentials to the outside world Third, a user dealing with many access networks needs to keep track of all the identities and credentials she needs for each access network and use them to start each communication session.

To turn off an individual bit, we can use either the reset() or the subscript operator Both of the following operations turn off bitvec's first bit:

// equivalent; turn off first bit bitvecreset( 0 ); bitvec[ 0 ] = 0;

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set() and reset() can also be used to, respectively, turn on or turn off the entire bitset object This is accomplished by invoking the desired operation without passing it a particular position For example:

// reset all the bits to 0 bitvecreset(); if ( bitvecnone() != true ) // oops! something is wrong // set all the bits to 1 bitvecset(); if ( bitvecany() != true ) // oops! again, something is wrong

, . (7.17)

The flip() operation reverses the value of either an individual bit or the entire bitset object:

bitvecflip( 0 ); // reverses value of first bit bitvec[0]flip(); // also reverses the first bit!

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